If diagonals of a parallelogram are left( {5hat{i} - 4hat{j} + 3hat{k}} right) and left(

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3-1.Vectors

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If diagonals of a parallelogram are $\left( {5\hat i - 4\hat j + 3\hat k} \right)$ and $\left( {3\hat i + 2\hat j - \hat k} \right)$ then its area is

A

$\sqrt {171} \,unit$

B

$\sqrt {72} \,unit$

C

$171\,unit$

D

$72\,unit$

Solution

Area $ = \frac{1}{2}\left| {\vec a \times \vec b} \right|$ here ${\vec a}$ and ${\vec b}$ are diagonals of parallelogram

Standard 11

Physics

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